The beta oxidization of cesium137 have a half-life of 30 years.How several yrs. must slip away to run down 25mg token to 6.25?

Ok so use y = (yo)(2) ^(-t/h)
Where
y = end amount
yo = resourceful amount
-t = time
h = halflife
So
6.25 = 25 * 2^ (-t/30)
***Divide both sides by 25***
0.25 = 2^(-t/30)
***take the log of both sides***
log(0.25) = (-t/30) log(2)
log (0.25) / log (2) = -t/30
(30) log(0.25) / log (2) = -t
-t = -60
t = 60
So the answer is... 60 years!
6.25=25 (.5) ^ (t/137)
6.25/25= .5^ (t/137)
(log (6.25/25)/log (.5)) * 137 = t
t= time it takes
hope this help
60 years. That's two half lives, disappearing a quarter of the original.
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